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Question

A nichrome wire has a resistance of \( 60 \, \Omega \) at \( 30^\circ \text{C} \) and \( \alpha = 1.7
\times 10^{-4} \, ^\circ\text{C}^{-1} \). What is its resistance at \( 330^\circ \text{C} \)?

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Explanation

**Resistance** R = ρ l/A, ρ resistivity (Ω·m), l length (m), A area (m²), ρ = m/(n e² τ) from Drude model, τ average collision time. Ohm's law V = I R holds when ρ constant, independent of V. Volume constant stretching l→2l implies A→A/2, so R' = ρ·2l/(A/2)=4R, resistance quadruples when length doubles at constant volume. Use: R_t = R₀ [1 + α (T - T₀)] . Substitute: R_t = 60 [1 + 1.7 × 10⁻⁴ (330 - 30)] . Calculate: R_t = 60 [1 + 1.7 × 10⁻⁴ × 300] = 60 [1 + 0.051] = 60 × 1.051 = 63.06 Ω .

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