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Question

Two cells in parallel have emf \( 8 \, \text{V} \) and \( 2 \, \text{V} \) with internal resistances \(
2 \, \Omega \) and \( 1 \, \Omega \). What is the equivalent emf?

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Explanation

**Resistivity** depends on material and temperature, not geometry. For metallic conductor, ρ ≈10⁻⁸ Ω·m for copper. Given ρ=4×10⁻⁸ Ω·m, l=2 m, A=π r², R calculation uses R=ρ l/A. Stretching wire conserves volume V = l A = l' A', so A' = A l/l', new R' = ρ l'²/V. For parallel: εₑq = (ε₁ r₂ + ε₂ r₁/r₁ + r₂) . Substitute: εₑq = (8 × 1 + 2 × 2/2 + 1) = (8 + 4/3) = (12/3) = 4 V . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε

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