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Question

A \( 15 \, \text{V} \) battery with negligible internal resistance is connected to a \( 3 \, \Omega \)
and \( 12 \, \Omega \) resistor in series. What is the power dissipated in the \( 12 \, \Omega \)
resistor?

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Explanation

**Cells combination** series ε_eq = Σ ε_i, r_eq = Σ r_i, parallel for identical cells ε_eq = ε, r_eq = r/n, n number of cells. Maximum current when external R = r_eq, power transfer theorem, explaining why matching resistances maximizes power. Total resistance: R = 3 + 12 = 15 Ω . Current: I = (V/R) = (15/15) = 1 A . Power: P = I² R = 1² × 12 = 12 W . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation

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