Skip to content

Question

What is the time (in seconds) required to deposit 0.355 g of cobalt from a CoSO₄ solution using a current of 0.2 A? (Atomic mass of Co = 59 g/mol, F = 96500 C/mol)

Options

Choose one · Correct answer highlighted

Explanation

Co²⁺ + 2e⁻ → Co . 1 mol Co (59 g) requires 2F. Moles = (0.355/59) = 0.006017 mol , Charge = 0.006017 × 2 × 96500 = 1161.24 C . t = (Q/I) = (1161.24/0.2) = 5806.2 s .

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.