Practice question
Question
What is the potential of a hydrogen electrode in a solution with pH = 2 at 298 K? (Given: E°H⁺/H_₂ = 0.00 V )
Explanation
E = E° - (0.059/n) log (1/[H⁺]) , [H⁺] = 10⁻² , n = 1 . E = 0 - 0.059 × 2 = -0.118 V .
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