What is the standard emf of a cell with the reaction Sn(s) + Pb²⁺(aq) → Sn²⁺(aq) + Pb(s) ? (Given: E°Sn²⁺/Sn = -0.14 V ,

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What is the standard emf of a cell with the reaction Sn(s) + Pb²⁺(aq) → Sn²⁺(aq) + Pb(s) ? (Given: E°Sn²⁺/Sn = -0.14 V , E°Pb²⁺/Pb = -0.13 V )

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0.01 V Correct 0.27 V -0.01 V 0.14 V

E°cell = E°cathode - E°anode = -0.13 - (-0.14) = 0.01 V .

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