Practice question
Question
In a dry cell, what is the oxidation state of manganese in the cathode product MnO(OH)?
Explanation
Cathode: MnO₂ + NH₄⁺ + e⁻ → MnO(OH) + NH₃ . In MnO₂ , Mn = +4; in MnO(OH) , Mn + 2(-2) + 1 = 0, Mn = +3.
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