Skip to content

Question

What is the refractive index of a medium if the speed of light in it is \( 1.8 \times 10^8 \,
\text{m/s} \) and in vacuum is \( 3.0 \times 10^8 \, \text{m/s} \)?

Options

Choose one · Correct answer highlighted

Explanation

**Incoherent sources** intensity adds I = I₁+I₂, no interference pattern because phase random, two independent sources cannot produce stable interference because phase difference fluctuates rapidly, coherent sources required with constant phase, laser coherent, visibility of fringes requires coherence, degree of coherence determines contrast. Refractive index n = (c/v) . c = 3.0 × 10⁸ m/s , v = 1.8 × 10⁸ m/s . n = (3.0 × 10⁸/1.8 × 10⁸) ≈ 1.67 . Using Δ = d sinθ, y = n λ D/d, a sinθ = n λ, I = I₀ cos²θ, n = c/v, sinC = 1/n, λ' = λ/n and A = 2a

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.