Skip to content

Question

What is the path difference for the sixth dark fringe in a double-slit experiment?

Options

Choose one · Correct answer highlighted

Explanation

**Incoherent sources** intensity adds I = I₁+I₂, no interference pattern because phase random, two independent sources cannot produce stable interference because phase difference fluctuates rapidly, coherent sources required with constant phase, laser coherent, visibility of fringes requires coherence, degree of coherence determines contrast. Destructive interference occurs at Δ = (n + (1/2))λ . For the sixth dark fringe, n = 5 , Δ = (5 + (1/2))λ = (11λ/2) . Using Δ = d sinθ, y = n λ D/d, a sinθ = n λ, I = I₀ cos²θ, n = c/v, sinC = 1/n, λ' = λ/n and A = 2a cos(φ/2), calculation gives

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.