Practice question
Question
What is the pressure of 0.4 moles of an ideal gas in a 4-litre container at 327°C? (R = 8.31 J mol⁻¹ K⁻¹)
Explanation
**Temperature dependence of RMS speed** v_rms ∝ √T, doubling T increases v_rms by √2≈1.414, e.g., at 300 K v_rms for O₂ ≈483 m/s, at 600 K ≈683 m/s, illustrating kinetic theory relation between temperature and molecular motion, average kinetic energy ½ m v_rms² =3/2 k_B T. PV = μ R T, P = (μ R T)/(V).T = 327 + 273 = 600 K, V = 4 × 10⁻³ m³.P = (0.4 × 8.31 × 600)/(4 × 10⁻³) = 4.986 × 10⁵ Pa ≈ 5.0 atm (1 atm ≈ 10⁵ Pa). Substituting values gives 5.0 atm, which matches expected kinetic theory result, confirming mean free path
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.