Practice question
Question
What is the pressure exerted by 1 mole of an ideal gas in a 10-litre container at 300 K? (R = 8.31 J mol^{-1 K^{-1)
Explanation
Given:
What is the pressure exerted by 1 mole of an ideal gas in a 10-litre container at 300 K? (R = 8.31 J mol^{-1 K^{-1)
These values define the system as per NCERT data.
Formula:
PV = μ R T, P = μ R T/V.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
P = frac1 × 8.31 × 30010 × 10â»Â³= 2.493 × 10âµ Pa approx 2.5 atm (1 atm approx 10âµ Pa).
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.