Practice question
Question
What is the mass defect of a nucleus with binding energy \( 167.67 \, \text{MeV} \)? (Given \( 1 \,
\text{u} = 931.5 \, \text{MeV/c}^2 \))
Explanation
**Mass defect** Δm = Z m_p + N m_n - M_nucleus, binding energy BE = Δm c², 1 u =931.5 MeV/c², BE per nucleon = BE/A, measures stability, peak ~8.8 MeV at Fe-56, for A=36 BE=288 MeV BE/A=8 MeV, for A=12 BE=96 MeV BE/A=8 MeV, for A=16 BE=127.5 MeV BE/A≈7.97 MeV, higher BE/A more stable. Δ M = (E_b/c²) . Δ M = (167.67/931.5) ≈ 0.18 u . Using E_n = -13.6/n² eV, r_n = n² a₀, L = n h/2π, R = R₀ A^¹/³, BE = Δm c² and 1 u = 931.5 MeV, evaluation yields 0.18 u, consistent with Bohr model and nuclear binding energy systematics.
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.