Practice question
Question
What is the intensity of light after passing through two polaroids with pass-axes at \( 60^\circ \), if
the intensity after the first is \( I_0 \)?
Explanation
**Polaroid rotation** intensity varies sinusoidally with angle due to Malus law I = I₀ cos²θ, when polaroid rotated 90° from initial, intensity goes from max to zero, for unpolarized light rotating polaroid does not change intensity after first polaroid because average, but second polaroid intensity depends on relative angle, explains why intensity transmitted through two polaroids drops to zero when perpendicular. Using Malus’ law, I = I₀ cos² θ . For θ = 60° , cos 60° = 0.5 , I = I₀ (0.5)² = 0.25 I₀ . Using Δ = d sinθ, y = n λ D/d, a sinθ = n λ, I =
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.