Practice question

Given: What is the escape speed from a planet of mass 4.8 × 10²⁴kg and radius 5 × 10⁶m ? ( G = 6.67 × 10⁻¹¹N m²/kg² ) These values define the system as per NCERT data. Formula: v_e = sqrt2 G M/R. This is standard NCERT relation. Substitution & Calculation: v_e = sqrtfrac2 × 6.67 × 10⁻¹¹ × 4.8 × 10²⁴⁵ × 10⁶. v_e = sqrt6.403 × 10⁷approx 8.0 × 10³m/s = 8.0 km/s . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.