Practice question

Given: A bus starts from rest and moves with a uniform acceleration of 1.5 m/s² for 8 s . What is the final velocity of the bus? These values define the system as per NCERT data. Formula: Use the equation v = v_0 + a t. This is standard NCERT relation. Substitution & Calculation: Here, initial velocity v_0 = 0, acceleration a = 1.5 m/s², time t = 8 s . Substitute: v = 0 + 1.5 · 8 = 12 m/s . The final velocity is 12 m/s . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.