Practice question

Given: What is the angular width of the ntral maximum in a single-slit diffraction pattern if the slit width is 5.0 μm and the wavelength is 650 nm ? Formula: Angular width 2θ = 2lambda/a. Substitution & Calculation: lambda = 6.5 × 10⁻⁷m, a = 5.0 × 10⁻⁶m . sin θ = lambda/a = frac6.5 × 10⁻⁷⁵.0 × 10⁻⁶= 0.13, θ = sin^{-1(0.13) approx 7.5°, 2θ approx 15° . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.