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Question

What happens to the torque on a rectangular current loop if the magnetic field direction is reversed?

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Explanation

**Solenoid field** inside long solenoid is B = μ₀ n I, n = N/L turns per meter (m⁻¹), uniform and parallel to axis, outside negligible for long solenoid because fields from opposite sides cancel. For n = 1200 m⁻¹, I = 1 A, B = 4π×10⁻⁷×1200 = 1.51×10⁻³ T = 1.51 mT. Torque is given by boldsymboltau = m × B . Reversing the magnetic field B reverses the direction of the torque vector, but its magnitude remains the same. Using F = q v B sinθ, F = I l B sinθ, B = μ₀ I/(2π r), B = μ₀ N I/(2R) and τ

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