Practice question

**Solenoid field** inside long solenoid is B = μ₀ n I, n = N/L turns per meter (m⁻¹), uniform and parallel to axis, outside negligible for long solenoid because fields from opposite sides cancel. For n = 1200 m⁻¹, I = 1 A, B = 4π×10⁻⁷×1200 = 1.51×10⁻³ T = 1.51 mT. B = (μ₀ I/2 π r) , so r = (μ₀ I/2 π B) . r = (4 π × 10⁻⁷ × 12/2 π × 2.4 × 10⁻⁶) = (48 × 10⁻⁷/4.8 × 10⁻⁶) = 1 m . Using F = q v B sinθ, F = I l B sinθ, B =