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Practice question

Question

What happens to the current in a purely capacitive AC circuit when the frequency of the source increases?

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Explanation

In a purely capacitive circuit, the capacitive reactance ( X_C = 1/omega C ) decreases as the frequency ( f, where omega = 2Ï€ f ) increases. Since current is inversely proportional to reactance ( I = V/X_C ), the current increases.

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