Practice question
Question
What happens to the current in a purely capacitive AC circuit when the frequency of the source increases?
Explanation
In a purely capacitive circuit, the capacitive reactance ( X_C = 1/omega C ) decreases as the frequency ( f, where omega = 2Ï€ f ) increases. Since current is inversely proportional to reactance ( I = V/X_C ), the current increases.
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