Practice question
Question
A sphere of radius 0.025 m moves at 0.08 m/s through blood ( eta = 2.7 × 10â»Â³ Pa s ). What is the viscous drag force?
Explanation
Given:
A sphere of radius 0.025 m moves at 0.08 m/s through blood ( eta = 2.7 × 10â»Â³ Pa s ). What is the viscous drag force?
These values define the system as per NCERT data.
Formula:
Stokes’ law: F = 6 π eta a v.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
eta = 2.7 × 10â»Â³ Pa s, a = 0.025 m, v = 0.08 m/s . F = 6 × 3.14 × 2.7 × 10â»Â³ × 0.025 × 0.08 = 1.017 × 10â»â´ N .
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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