Practice question

**Energy distribution** shows maximum kinetic at equilibrium and maximum potential at extremes, sum constant. This relation enables calculation of amplitude, velocity at any displacement via v = ±√(2(E-U)/m), and understanding of energy storage in oscillating system for NEET problems. In SHM, energy oscillates between kinetic and potential forms, while in uniform circular motion, kinetic energy remains constant due to constant speed. Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result SHM cycles between kinetic and potential energy follows, reflecting SHM dependence on amplitude A, ω and system parameters.