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Question

In SHM, if the particle is at an extreme position, what can be inferred about its kinetic energy?

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Explanation

**Energy in SHM** interconverts between kinetic K = ½ m v² = ½ m ω² (A² - x²) and potential U = ½ k x² = ½ m ω² x², total E = K + U = ½ k A² = ½ m ω² A² constant, independent of time. At mean position x=0, E = K_max = ½ m ω² A², at extremes x=±A, E = U_max = ½ k A². At the extreme position ( x = ± A ), velocity is zero ( v = 0 ), so kinetic energy ( K = (1/2) m v² ) is zero, with all energy being

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