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Question

Two waves \( y_1 = 5 \sin (6x - 12t) \) and \( y_2 = 5 \sin (6x - 12t + \frac{\pi}{3}) \) interfere.
What is the amplitude of the resultant wave?

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Explanation

**Interference of waves** produces enhancement or cancellation based on phase. Two equal amplitude waves out of phase by π cancel completely, A = 0, while in-phase superposition doubles amplitude to 2a, demonstrating energy redistribution without violation of conservation. Amplitude: A = 2a cos (Φ/2) , a = 5 m , Φ = (π/3) . A = 2 × 5 cos (π/6) = 10 × (√(3)/2) = 5√(3) ≈ 8.66 m . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 8.7 m, illustrating frequency-length-speed interdependence and quantization by boundaries.

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