Practice question
Question
Two waves \( y_1 = 5 \sin (7x - 14t) \) and \( y_2 = 5 \sin (7x - 14t + \frac{\pi}{2}) \) interfere.
What is the amplitude of the resultant wave?
Explanation
**Superposition principle** states resultant displacement equals algebraic sum of individual waves, y = y₁ + y₂. For coherent waves with phase difference φ, resultant amplitude A = √(a₁² + a₂² + 2a₁a₂ cosφ), equal amplitudes give A = 2a cos(φ/2), constructive when φ = 2nπ, destructive when φ = (2n+1)π. Amplitude: A = 2a cos (Φ/2) , a = 5 m , Φ = (π/2) . A = 2 × 5 cos (π/4) = 10 × (1/√(2)) ≈ 7.07 m . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 7 m, illustrating frequency-length-speed interdependence and quantization by boundaries.
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