Practice question
Question
The van’t Hoff factor of a 0.08 m CaCl₂ solution is 2.6. What is the boiling point elevation? ( Kb = 0.52 K kg mol⁻¹ )
Explanation
Δ Tb = i · Kb · m . Δ Tb = 2.6 × 0.52 × 0.08 ≈ 0.1082 K .
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