Practice question
Question
What is the mass of urea (molar mass = 60 g/mol) required to prepare 2 kg of a 0.5 molal aqueous solution?
Explanation
Molality = (Moles of solute/Mass of solvent in kg) . Moles = 0.5 × 2 = 1 mol . Mass = 1 × 60 = 60 g .
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