Practice question

MCQ

Question

The distance x of a particle moving along a straight line from a fixed point on the line at time t after start is given by t = ax² + bx + c (a, b, c are positive constants). If v be the velocity of the particle and u(≠0) be the initial velocity of the particle then which one is correct?

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1/v² + 1/u² = 4at 1/v² + 1/u² = -4at 1/v² – 1/u² = 4at Correct 1/v² – 1/u² = -4at

Let's break it down: complete solution: write formula, plug data, do arithmetic. Final value matches 1/v² – 1/u² = 4at. Simple and accurate.

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