Practice question
Question
A particle moves in a straight line and its velocity v at time t seconds is given byv = 3t² – 4t + 5 cm/second. What will be the distance travelled by the particle during first 3 seconds after the start?
Explanation
Applying the basic concept, using formula we get 24 cm. Calculation gives this directly, check steps: apply rule, substitute values, simplify to get 24 cm.
Related blogs
Guides and insights connected to this topic
Coronavirus Structure, Genome, Replication, Symptoms, Pathogenesis, and Prevention
Structure of Coronavirus Coronaviruses (enveloped RNA viruses) fall in the virus family Coronaviridae, order Nidovirales. They are enveloped...
Human Astrovirus- An Introduction
Structure of Human Astrovirus Human astrovirus (virus causing gastroenteritis in humans) falls under Astroviridae (virus family) and genus M...
TRUST (Toludine Red Unheated Serum Test) For Syphilis
Principle The TRUST reagent containing modified VDRL antigen and toludine red pigment particles, flocclulate when mixed with sample containi...
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.