Practice question
Question
Specimens for light microscopy are commonly fixed with a solution containing chemicals that crosslink/denature cellular constituents . Commonly used fixatives such as formaldehyde and methanol could act in various ways as described below: A. Formaldehyde crosslinks amino groups on adjacent molecules and stabilizes protein-protein and protein-nucleic acid interactions. B . Methanol acts as a denaturing fixative and acts by reducing the solubility of protein molecules by disrupting hydrophobic interactions . C. Formaldehyde crosslinks lipid tails in biological membranes . D. Methanol acts on nucleic acids. crosslinks nucleic acids with proteins and thus stabilizes protein-nucleic acid interactions. Which one of the following combinations represents all correct statements?
Explanation
In specimens for light microscopy are commonly fixed, A and B represents established outcome. functional assays confirms option D (A and B) as correct, while alternatives misstate substrate or regulatory direction, contradicting textbook data.
Discussion
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