Practice question

Given: In the Carius method, the percentage of sulphur in a 0.3 g compound yielding 0.699 g BaSO₄ is (Atomic masses: Ba = 137, S = 32, O = 16) These values define the system as per NCERT data. Formula: Molar mass of BaSO₄ = 137 + 32 + 64 = 233 g/mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Mass of S = 32 × 0.699/233 = 0.096 g. Percentage = 0.096 × 100/0.3 = 32% . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.