Practice question

MCQ

Question

In order to clone an eukaryotic gene in pBR322 plasmid vector, the desired DNA fragment was produced by PstI cleavage and incubated with PstI digested pRR322 (PstI cleavage site lies within the ampicillin resistant gene) and ligated. Mixtures of ligated cells were used to transform E. coli and plasmid containing bacteria were selected by their growth in tetracycline containing medium. Which type of plasmid/s will be found?

Options

Choose one · Correct answer highlighted

Circular pBR322 plasmid containing the target gene and resistant to only tetracycline. Circular pBR322 plasmid containing the target gene and resistant to tetracycline only and re-circularized pBR322 plasmid resistant to both ampicillin and tetracycline. Circular pBR322 plasmid containing the target gene and resistant to only tetracycline, re-circularized pBR322 resistant to both ampicillin and tetracycline and concatemerised pBR322 resistant to both ampicillin and tetracycline. Correct Circular pBR322 plasmid containing the target gene and resistant to both ampicillin and tetracycline.

Explanation

Analysis of in order to clone an eukaryotic gene shows Circular pBR322 plasmid containing the target gene and resis represents established outcome. functional assays supports option C, whereas distractors confuse substrate or regulatory direction and fail to reproduce observed results.

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