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Question

How many grams of CuSO₄ are required to produce 3.2 g of Cu with excess Zn? (Molar masses: CuSO₄ = 159.5 g/mol, Cu = 64 g/mol)

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Explanation

Reaction: CuSO₄ + Zn → Cu + ZnSO₄. Moles of Cu = 3.2/64 = 0.05 mol. 1 mol Cu from 1 mol CuSO₄; mass = 0.05 × 159.5 ≈ 8 g.

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