Practice question
Question
How many grams of AgNO₃ are required to produce 5.75 g of AgCl with excess NaCl? (Molar masses: AgNO₃ = 170 g/mol, AgCl = 143.5 g/mol)
Explanation
Reaction: AgNO₃ + NaCl → AgCl + NaNO₃. Moles of AgCl = 5.75/143.5 ≈ 0.04 mol. 1 mol AgCl from 1 mol AgNO₃; mass = 0.04 × 170 = 6.8 g.
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.