Skip to content

Question

How many grams of AgNO₃ are required to produce 5.75 g of AgCl with excess NaCl? (Molar masses: AgNO₃ = 170 g/mol, AgCl = 143.5 g/mol)

Options

Choose one · Correct answer highlighted

Explanation

Reaction: AgNO₃ + NaCl → AgCl + NaNO₃. Moles of AgCl = 5.75/143.5 ≈ 0.04 mol. 1 mol AgCl from 1 mol AgNO₃; mass = 0.04 × 170 = 6.8 g.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.