Practice question
Question
How many grams of NaCl are produced when 10.6 g of Na₂CO₃ reacts with excess HCl? (Molar masses: Na₂CO₃ = 106 g/mol, NaCl = 58.5 g/mol)
Explanation
Reaction: Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O. Moles of Na₂CO₃ = 10.6/106 = 0.1 mol. 1 mol Na₂CO₃ produces 2 mol NaCl; 0.1 mol produces 0.2 mol. Mass = 0.2 × 58.5 = 11.7 g.
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