Practice question
Question
For the reaction 2COâ‚‚(g) <=> 2CO(g) + Oâ‚‚(g), K_c = 0.01 at 1000 K. If initial [COâ‚‚] = 0.5 M, what is [CO] at equilibrium?
Explanation
Given:
For the reaction 2COâ‚‚(g) <=> 2CO(g) + Oâ‚‚(g), K_c = 0.01 at 1000 K. If initial [COâ‚‚] = 0.5 M, what is [CO] at equilibrium?
These values define the system as per NCERT data.
Formula:
Let [CO] = 2x, [Oâ‚‚] = x, [COâ‚‚] = 0.5 - 2x.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
K_c = frac[CO]² [O₂][CO₂]² = (2x)² · x/(0.5 - 2x)² = 0.01 . 4x³/(0.5 - 2x)² = 0.01, solve: x approx 0.027, 2x approx 0.054 M.
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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