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Practice question

Question

For the reaction 2COâ‚‚(g) <=> 2CO(g) + Oâ‚‚(g), K_c = 0.01 at 1000 K. If initial [COâ‚‚] = 0.5 M, what is [CO] at equilibrium?

Options

Choose one · Correct answer highlighted

Explanation

Given: For the reaction 2CO₂(g) <=> 2CO(g) + O₂(g), K_c = 0.01 at 1000 K. If initial [CO₂] = 0.5 M, what is [CO] at equilibrium? These values define the system as per NCERT data. Formula: Let [CO] = 2x, [O₂] = x, [CO₂] = 0.5 - 2x. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: K_c = frac[CO]² [O₂][CO₂]² = (2x)² · x/(0.5 - 2x)² = 0.01 . 4x³/(0.5 - 2x)² = 0.01, solve: x approx 0.027, 2x approx 0.054 M. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

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