Practice question
Question
For C(s) + H₂O(g) <=> CO(g) + H₂(g), K_p = 0.4 atm at 1000 K. If initial p_{H₂O = 1 atm, what is p_{CO at equilibrium?
Explanation
Given:
For C(s) + H₂O(g) <=> CO(g) + H₂(g), K_p = 0.4 atm at 1000 K. If initial p_{H₂O = 1 atm, what is p_{CO at equilibrium?
These values define the system as per NCERT data.
Formula:
Let p_{CO = p_{H₂ = x, p_{H₂O = 1 - x.
This is standard NCERT relation.
Substitution & Calculation:
K_p = fracp_{CO · p_{H₂p_{H₂O = x²/1 - x = 0.4 . x² = 0.4 - 0.4x, x² + 0.4x - 0.4 = 0, x approx 0.44 atm.
Result:
The computed value matches expected outcome and confirms correct choice as per NCERT.
Discussion
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