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Question

For A(g) <=> 2B(g) , Kc = 0.25 at 500 K. If 0.4 mol A is in a 1 L vessel, what is [B] at equilibrium?

Options

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Explanation

Initial: [A] = 0.4 M , [B] = 0 . Let 2x = [B] , [A] = 0.4 - x . Kc = ([B]²/[A]) = ((2x)²/0.4 - x) = 0.25 , 4x² = 0.1 - 0.25x , x ≈ 0.125 , [B] = 0.25 M .