Practice question
Question
For a reaction with Δ G° = -20 kJ/mol at 298 K, what is the equilibrium constant K? (R = 8.314 J/mol·K)
Explanation
Δ G° = -RT ln K, -20 × 10³ = -8.314 × 298 × ln K, ln K = 8.07, K = e⁸.⁰⁷ ≈ 3160.
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