Practice question
Question
For an ideal gas ( γ = 1.4 ) expanding adiabatically from 6 L to 12 L at 500 K, calculate the work done if Cv = 20.785 J/mol·K . (1 mol gas)
Explanation
For adiabatic expansion, T₂ = 500 × (6/12)⁰.⁴ ≈ 500 × 0.7579 = 378.9 K . Then, Δ T = 378.9 - 500 = -121.1 K . Work done: w = nCvΔ T = 1 × 20.785 × (-121.1) ≈ -2516 J .
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