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Question

For 2AB(g) <=> A₂(g) + B₂(g) , Kp = 0.25 at 600 K. If the initial pressure of AB is 4 atm, what is PA₂ at equilibrium?

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Explanation

Let PA₂ = PB₂ = x , PAB = 4 - 2x , total pressure = 4 - 2x + 2x = 4 . Kp = (PA₂ PB₂/(PAB)²) = (x²/(4 - 2x)²) = 0.25 , (x/4 - 2x) = 0.5 , x = 2 - x , 2x = 2 , x = 1 atm .

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