Practice question
Question
Calculate the bond enthalpy of O=O in O₂(g) given: Δ Hf° (H₂O,g) = -241.8 kJ/mol, H-H = 436 kJ/mol, O-H = 463 kJ/mol.
Explanation
For H₂(g) + (1/2)O₂(g) → H₂O(g), Δ H = -241.8 kJ. Bonds broken: H-H (436) + (1/2)O=O. Bonds formed: 2(O-H) = 2 × 463 = 926. Δ H = (436 + (1/2)O=O) - 926 = -241.8, (1/2)O=O = 248.2, O=O = 496.4 kJ/mol.
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