Practice question
Question
Calculate Δ H for 2C(s) + H₂(g) → C₂H₂(g) given: C₂H₂(g) + (5/2)O₂(g) → 2CO₂(g) + H₂O(l), Δ H = -1299.5 kJ/mol; C(s) + O₂(g) → CO₂(g), Δ H = -393.5 kJ/mol; H₂(g) + (1/2)O₂(g) → H₂O(l), Δ H = -285.8 kJ/mol.
Explanation
Reverse first: Δ H = 1299.5 kJ. Second (×2): Δ H = -787 kJ. Third: Δ H = -285.8 kJ. Add: 1299.5 - 787 - 285.8 = 226.7 kJ/mol.
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