Practice question
Question
An electron jumps from n = 4 to n = 1 in a hydrogen atom. What is the energy of the emitted photon? (E₁ = -2.18 × 10⁻¹⁸ J)
Explanation
ΔE = |E₁|(1 - 1/16) = 2.04375×10⁻¹⁸ J.
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