Skip to content

Question

The ratio of the velocities of an electron in the second orbit of H to the third orbit of Li²⁺ is: (v₁ for H = 2.19 × 10⁶ m s⁻¹)

Options

Choose one · Correct answer highlighted

Explanation

For H (Z=1), v₂ = 2.19×10⁶ / 2 = 1.095×10⁶ m s⁻¹. For Li²⁺ (Z=3), v₃ = 3 × 2.19×10⁶ / 3 = 2.19×10⁶ m s⁻¹. Ratio = 0.5.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.