Skip to content

#atomic physics

21 public questions tagged with this topic.

The speed of an electron in the first orbit of a hydrogen atom is 2.2 × 10⁶ m/s . What is its speed in the second orb

Given: The speed of an electron in the first orbit of a hydrogen atom is 2.2 × 10⁶ m/s . What is its speed in the second orbit? These values define the system as per NCERT data. Formula: v_n = v_1/n, v_1 = 2.2 × 10⁶ m/s. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: For n = 2 : v_2 = 2.2 × 10⁶/2 = 1.1 × 10⁶ m/s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Dual Nature, Atoms, Nuclei and Electronic Devices, Topic: Atomic structure, nuclear binding and semiconductor physics.

Which subshell has the lowest energy for n = 4 in a multi-electron atom?

Given: Which subshell has the lowest energy for n = 4 in a multi-electron atom? These values define the system as per NCERT data. Formula: For n = 4, 4s (l = 0) has the lowest energy, followed by 4p, 4d, 4f.. This is standard NCERT relation. Substitution & Calculation: In multi-electron atoms, energy increases with l for a given n. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: d and f Block Elements, Topic: Lanthanoid contraction due to poor shielding of 4f orbitals.

The ratio of the velocities of an electron in the second orbit of H to the third orbit of Li²⁺ is: (v₁ for H = 2.19 × 10

For H (Z=1), v₂ = 2.19×10⁶ / 2 = 1.095×10⁶ m s⁻¹. For Li²⁺ (Z=3), v₃ = 3 × 2.19×10⁶ / 3 = 2.19×10⁶ m s⁻¹. Ratio = 0.5.

Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Developments Leading to Bohr Model - Electromagnetic Radiation and Spectrum