An electron in a hydrogen atom transitions from n = 3 to n = 2. What is the wavenumber of the emitted light? (RH = 1.097

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An electron in a hydrogen atom transitions from n = 3 to n = 2. What is the wavenumber of the emitted light? (RH = 1.097 × 10⁷ m⁻¹)

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2.742 × 10⁶ m⁻¹ 1.5236 × 10⁶ m⁻¹ Correct 3.291 × 10⁶ m⁻¹ 1.097 × 10⁷ m⁻¹

ν̄ = RH (1/4 - 1/9) = 1.5236×10⁶ m⁻¹.

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