Practice question
Question
The angular momentum of an electron in the fourth orbit of He⁺ is 4.22 × 10⁻³⁴ J s. What is the frequency of the photon emitted when it falls to the second orbit? (h = 6.626 × 10⁻³⁴ J s, E₁ for H = -2.18 × 10⁻¹⁸ J)
Explanation
n=4. ΔE ≈ 1.635×10⁻¹⁸ J. ν ≈ 2.467×10¹⁵ Hz.
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