Practice question

Given: An aluminium block of dimensions 0.5 m × 0.3 m × 0.1 m is subjected to a shearing force of 7 × 10⁴N . If the shear modulus of aluminium is 2.5 × 10¹⁰N/m², what is the displacement of the top face? These values define the system as per NCERT data. Formula: Shear modulus: G = F / A/Δ x / L. This is standard NCERT relation. Substitution & Calculation: Rearrange: Δ x = F L/A G . Area: A = 0.5 × 0.3 = 0.15 m², L = 0.1 m . Substitute: Δ x = frac7 × 10⁴ × 0.10.15 × 2.5 × 10¹⁰= 7000/3.75 × 10⁹approx 1.87 × 10⁻⁶m . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.