Practice question
Question
A wire of length \( 10 \, \text{m} \) and cross-sectional area \( 1 \times 10^{-6} \, \text{m}^2 \) has
a resistance of \( 20 \, \Omega \). What is the resistivity of the material?
Explanation
**Temperature dependence** of resistance R_t = R₀[1+α(T-T₀)], α temperature coefficient (per °C), R₀ resistance at T₀ (Ω). For metals α positive ≈10⁻³ /°C, resistance increases with temperature because τ decreases due to increased phonon scattering, n nearly constant. Resistance: R = (rho l/A) . Rearrange: rho = (R A/l) . Substitute: rho = (20 × 1 × 10⁻⁶/10) = 2 × 10⁻⁶ Ω m . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation yields 2.0 × 10⁻⁶ Ω m,
Discussion
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