Practice question
Question
A system of two particles, 3kg at (1,2) and 1kg at (5,6), moves as a rigid body. What is the distance of the center of mass from the origin?
Explanation
X = (3×1)+(1×5)3+1 = 3+54 = 2. Y = (3×2)+(1×6)3+1 = 6+64 = 3. Distance = X2+Y2 = 22+32 = 4+9 = 13≈3.6m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.6 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Related blogs
Guides and insights connected to this topic
Patterns in Life: Diversity and Classification Notes - Five Kingdom, Binomial Nomenclature and Hierarchy
Learn about biodiversity, the five kingdoms, binomial nomenclature and taxonomic hierarchy, and why classification matters for ecosystems and agriculture.
Cell: The Building Block of Life Notes - Structure, Organelles, Division and Cell Theory
Explore the blog post 'Rest' covering goo time in a concise read.
Body Fluids and Circulation Biology Notes - Blood, Blood Groups, Heart, Cardiac Cycle, ECG, Double Circulation and Disorders
Overview of circulatory systems, heart chambers across vertebrates, single vs double circulation, blood groups and ECG basics.
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.